96=192-28x+x^2

Solution for 96=192-28x+x^2 equation:

96=192-28x+x^2

We move all terms to the left:

96-(192-28x+x^2)=0

We get rid of parentheses

-x^2+28x-192+96=0

We add all the numbers together, and all the variables

-1x^2+28x-96=0

a = -1; b = 28; c = -96;
Δ = b2-4ac
Δ = 282-4·(-1)·(-96)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-20}{2*-1}=\frac{-48}{-2}
=+24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+20}{2*-1}=\frac{-8}{-2}
=+4
$